document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785747>Question 785747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When 391758 and 394915 are divided by a certain three digit number, the three digit remainder is the same i each case. Find the divisor. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477697 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 391758-394915 ==3157\r<BR>\n" );
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document.write( "391 758 and 394 915 have the same remainder when divided by a certain three digit number.\r<BR>\n" );
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document.write( "The difference between 391 758 and 394 915  has remainder  zero when divided by this number.\r<BR>\n" );
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document.write( " Factors of 3 157 = 7*11*41 so 3 157 \r<BR>\n" );
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document.write( "77*41 Or<BR>\n" );
document.write( "287 *11 <BR>\n" );
document.write( "OR 11*44=451<BR>\n" );
document.write( "either 287 is the number OR 451 is the number since divisor is 3 digit.\r<BR>\n" );
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document.write( "Divide both the numbers by 287 and 451. to find out which gives same remainder\r<BR>\n" );
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