document.write( "Question 785549: The perimeter of a rectangle is 30 m. If one side is x, express the area of the rectangle in terms of x. Show that there is no value of x such that the area is 60m^2.\r
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Algebra.Com's Answer #477694 by KMST(5328)\"\" \"About 
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\"x\" = length of one side in meters
\n" ); document.write( "\"y\" = length of the adjacent side in meters
\n" ); document.write( "(one is the length of the rectangle, and the other one is the width)
\n" ); document.write( "The perimeter (in meters) is
\n" ); document.write( "\"2x%2B2y=30\" --> \"x%2By=15\" --> \"y=15-x\"
\n" ); document.write( "The area is
\n" ); document.write( "\"area=x%2Ay\"
\n" ); document.write( "Substituting \"15-x\" for \"y\", we get
\n" ); document.write( "\"area=x%2815-x%29\" <--> \"area=15x-x%5E2\" (area expressed in terms of x)
\n" ); document.write( "THat is a quadratic function.
\n" ); document.write( "It graphs as a parabola, and the vertex is a maximum.
\n" ); document.write( "(It is realy a portion of a parabola, because we must only define it for
\n" ); document.write( "\"0%3Cx%3C15\" to have positive numbers for width odf the rectangle.
\n" ); document.write( "\"area=15x-x%5E2\"-->\"area=-x%5E2%2B15x-56.25%2B56.25\"-->\"area=-%28x%5E2-15x-56.25%29%2B56.25\"-->\"area=-%28x-7.5%29%5E2%2B56.25\"
\n" ); document.write( "The maximum area is found when \"x=7.5\", and it is \"56.25\".
\n" ); document.write( "At that point \"y=15-7.5=7.5\" and the rectangle is a square.
\n" ); document.write( "For any other value of \"x\", tyhe area is less than that:
\n" ); document.write( "\"%28x-7.5%29%5E2%3E0\", \"-%28x-7.5%29%5E2%3C0\", and \"area=-%28x-7.5%29%5E2%2B56.25%3C56.25\"
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