document.write( "Question 785534: Mary drove to the train station and back. It took two hours less time to get there than it did to get back. The average s[ed on the trip there was 50 mph. The average speed on the way back was 30mph. How many hours did the trip there take? \n" ); document.write( "
Algebra.Com's Answer #477690 by KMST(5328)\"\" \"About 
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\"t\" = hours takem for the round trip
\n" ); document.write( "\"r\" = hours taken for the return trip
\n" ); document.write( "\"t=r%2B%28r-2%29\"-->\"t=2r-2\"-->\"t%2B2=2r\"-->\"r=%28t%2B2%29%2F2\"
\n" ); document.write( "\"d\" = distance to the station = distance traveled back from the station
\n" ); document.write( "For the round trip we know that
\n" ); document.write( "\"50t=2d\"
\n" ); document.write( "For the return trip we know that
\n" ); document.write( "\"d=30%28%28t%2B2%29%2F2%29\"-->\"d=30%28t%2B2%29%2F2\"-->\"d=15%28t%2B2%29\"-->\"d=15t%2B30\"
\n" ); document.write( "Substtituting that expression for \"d\" into \"50t=2d\" we get
\n" ); document.write( "\"50t=2%2A%2815t%2B30%29\"-->\"50t=30t%2B60\"-->\"50t-30t=60\"-->\"20t=60\"-->\"highlight%28t=3%29\"
\n" ); document.write( "Unfortunately, what that means for the trip distances and speeds is scary:
\n" ); document.write( "\"2d=50%2A3\"-->\"2d=150\"-->\"d=150%2F2=75\"
\n" ); document.write( "\"r=%283%2B2%29%2F2\"-->\"r=2.5\"
\n" ); document.write( "If the trip back took 2.5 hours and the trip to the station took 2hours less,
\n" ); document.write( "\"2.5h-2h=0.5h\",
\n" ); document.write( "Mary drove the 75 miles to the station in 0.5 hours.
\n" ); document.write( "Her average speed when going to the station was
\n" ); document.write( "\"75miles%2F%28%220.5+hours%22%29=150mph\"
\n" ); document.write( "
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