document.write( "Question 785534: Mary drove to the train station and back. It took two hours less time to get there than it did to get back. The average s[ed on the trip there was 50 mph. The average speed on the way back was 30mph. How many hours did the trip there take? \n" ); document.write( "
Algebra.Com's Answer #477690 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For the round trip we know that \n" ); document.write( " \n" ); document.write( "For the return trip we know that \n" ); document.write( " \n" ); document.write( "Substtituting that expression for \n" ); document.write( " \n" ); document.write( "Unfortunately, what that means for the trip distances and speeds is scary: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If the trip back took 2.5 hours and the trip to the station took 2hours less, \n" ); document.write( " \n" ); document.write( "Mary drove the 75 miles to the station in 0.5 hours. \n" ); document.write( "Her average speed when going to the station was \n" ); document.write( " |