document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785670>Question 785670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank holds 40 liters of a chemical solution. Currently, the solution has a strength of 10%. How much of this should be drained and replaced with 50% solution to get a final strength of 30%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477676 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A tank holds 40 liters of a chemical solution. Currently, the solution has a strength of 10%. How much of this should be drained and replaced with 50% solution to get a final strength of 30%?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active-active + active = active<BR>\n" );
document.write( "0.10*40 - 0.10x + 0.50x = 0.30*40<BR>\n" );
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document.write( "10*40 - 10x + 50x = 30*40<BR>\n" );
document.write( "40x = 20*40<BR>\n" );
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document.write( "x = 20 liters (amt. to be removed and replaced)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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