document.write( "Question 67182This question is from textbook Algebra 1
\n" ); document.write( ": In 1927 Charles Lindbergh flew the Spirit of St. Louis from New York to Paris at an average speed of 107.4 mi/h. Eleven years later, Howard Hughes flew the same route, averaged 217.1 mi/h, and took 16 hours, 57 minutes less time. Find the length of their route.
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Algebra.Com's Answer #47765 by josmiceli(19441) $\"\"$ $\"About$

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The distance is the same for each flyer
\n" ); document.write( " $\"d%5B1%5D+=+d%5B2%5D\"$
\n" ); document.write( " $\"r%5B1%5D%2At%5B1%5D+=+r%5B2%5D%2At%5B2%5D\"$
\n" ); document.write( " $\"107.4t+=+217.1%28t+-+16.95%29\"$
\n" ); document.write( " $\"107.4t+=+217.1t+-+3679.85\"$
\n" ); document.write( " $\"109.7t+=+3679.85\"$
\n" ); document.write( " $\"t+=+33.54\"$ hrs
\n" ); document.write( " $\"t+-+16.95+=+16.59\"$ hrs
\n" ); document.write( "Lindbergh's distance was
\n" ); document.write( " $\"r%5B1%5D%2At%5B1%5D+=+107.4%2A33.54\"$
\n" ); document.write( " $\"r%5B1%5D%2At%5B1%5D+=+3602\"$ mi
\n" ); document.write( "Hugh's distance should be the same
\n" ); document.write( " $\"r%5B2%5D%2At%5B2%5D+=+217.1%2A16.59\"$
\n" ); document.write( " $\"r%5B2%5D%2At%5B2%5D+=+3602\"$ mi \n" ); document.write( "

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