document.write( "Question 785500: solve 3sin(2x+40)=2cos(2x+40) where 0\n" ); document.write( "
Algebra.Com's Answer #477586 by Alan3354(69443)\"\" \"About 
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solve 3sin(2x+40)=2cos(2x+40) where 0 < x <360
\n" ); document.write( "sub t for 2x+40 (saves typing)
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\n" ); document.write( "3sin(t) = 2cos(t)
\n" ); document.write( "9sin^2 = 4cos^2 = 4(1 - sin^2)
\n" ); document.write( "9sin^2 = 4 - 4sin^2
\n" ); document.write( "13sin^2 = 4
\n" ); document.write( "sin^2 = 4/13
\n" ); document.write( "sin(2x+40) = +2sqrt(13)/13
\n" ); document.write( "x = 356.845 degs
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\n" ); document.write( "sin(2x+40) = -2sqrt(13)/13
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\n" ); document.write( "x = 323.155 degs
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