document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=784542>Question 784542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if tan^2 theta + cot^2 theta = 2 theta is an acute angle then tan^3 theta + cost^3 theta is equal to <BR>\n" );
document.write( "a)2<BR>\n" );
document.write( "b)3<BR>\n" );
document.write( "c)4<BR>\n" );
document.write( "d)8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477527 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if tan^2 theta + cot^2 theta = 2 theta is an acute angle then tan^3 theta + cost^3 theta is equal to<BR>\n" );
document.write( "***<BR>\n" );
document.write( "tan^2x+cot^2x=2<BR>\n" );
document.write( "tan^2x+1/tan^2x=2<BR>\n" );
document.write( "tan^4x+1=2tan^2x<BR>\n" );
document.write( "tan^4x-2tan^2x+1=0<BR>\n" );
document.write( "(tan^2x-1)(tan^2x-1)=0<BR>\n" );
document.write( "tan^2x=1<BR>\n" );
document.write( "tanx=1<BR>\n" );
document.write( "cotx=1<BR>\n" );
document.write( "...<BR>\n" );
document.write( "use sum of cubes formula<BR>\n" );
document.write( "tan^3x+cot^3x<BR>\n" );
document.write( "=(tanx+cotx)(tan^2x-tanxcotx+cot^2x)<BR>\n" );
document.write( "=(1+1)(1-1+1)=2(ans:a)<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );