document.write( "Question 67146This question is from textbook punchline: bridge to algebra
\n" ); document.write( ": O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it? \n" ); document.write( "
Algebra.Com's Answer #47752 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
O.k the problems are:(-7)to the power of 5 times (-7) times the power of -2. It said on the worksheet to wite the product without exponents. How can you solve it?\r
\n" ); document.write( "\n" ); document.write( "((-7)^5)((-7)^-2)\r
\n" ); document.write( "\n" ); document.write( "Lets first look at each term separately:\r
\n" ); document.write( "\n" ); document.write( "(-7)^5=-7*-7*-7*-7*-7\r
\n" ); document.write( "\n" ); document.write( "(-7)^-2=1/(-7^2)=1/(-7*-7)
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\n" ); document.write( "((-7)^5)((-7)^-2)=(7*-7*-7*-7*-7)(1/(-7*-7) when we cancel the 7's, we will have 3 sevens left in the numerator:
\n" ); document.write( "((-7)^5)((-7)^-2)=-7^3=-7*-7*-7 \r
\n" ); document.write( "\n" ); document.write( "Multiply -7*-7*-7 =49*-7=-343\r
\n" ); document.write( "\n" ); document.write( "Another way to look at it:\r
\n" ); document.write( "\n" ); document.write( "When you multiply, you add exponents, so:\r
\n" ); document.write( "\n" ); document.write( "((-7)^5)((-7)^-2)=((-7)^(5-2))=(-7)^3=-343\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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