document.write( "Question 785381: how we find lentgh of the diagonal in a regular pentagon whose length of the side is 3units? \n" ); document.write( "
Algebra.Com's Answer #477512 by KMST(5328)\"\" \"About 
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The exterior angles of a regular polygon with \"n\" sidees measure
\n" ); document.write( "\"360%5Eo%2Fn\" or, in radians, \"2pi%2Fn\".
\n" ); document.write( "The interior angles, being supplementary measure
\n" ); document.write( "\"180%5Eo-360%5Eo%2Fn=%28n%2A180%5Eo-360%5Eo%29%2Fn=%28n-2%29180%5Eo%2Fn\" or
\n" ); document.write( "\"pi-2pi%2Fn=+%28n-2%29pi%2Fn\"
\n" ); document.write( "The interior angles of a regular pentagon measure
\n" ); document.write( "\"3%2A180%5Eo%2F5=108%5Eo\" or \"3pi%2F5\"
\n" ); document.write( "Two sides of the pentagon and a diagonal form an isosceles triamgle with a vertex angle measuring \"3%2A180%5Eo%2F5=108%5Eo\" or \"3pi%2F5\", and two base angles measuring
\n" ); document.write( "\"%28180%5Eo-108%5Eo%29%2F2=72%5Eo%2F2=36%5Eo\" or \"%281%2F2%29%2A%28pi-3pi%2F5%29=%281%2F2%29%2A%282pi%2F5%29=pi%2F5\".
\n" ); document.write( "In the case of the problem the diagonal is the base and the legs are the sides of length 3 units, so half of the base would be
\n" ); document.write( "\"3cos%2836%5Eo%29\" or \"3cos%28pi%2F5%29\"
\n" ); document.write( "The length of the diagonal would be twice that long, approx. 4.854 units.
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