document.write( "Question 785382: Find an equation of the line that passes through the given point and is perpendicular to the given line. Write the equation in slope-intercept form. \r
\n" ); document.write( "\n" ); document.write( "(8, −4), 5x = 7y − \n" ); document.write( "
Algebra.Com's Answer #477498 by mananth(16946)\"\" \"About 
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5 x + -7 y = -6
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-7 y = -5 x -6
\n" ); document.write( "Divide by -7
\n" ); document.write( " y = 5/ 7 x + 6/7
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 5/7
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -1 2/5
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be -1 2/5
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\n" ); document.write( "m= -7/5 ,point ( 8 , -4 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-4 = -56/ 5 + b
\n" ); document.write( "b= 365
\n" ); document.write( "m= -7/5
\n" ); document.write( "The required equation is y = -7/ 5 x + 36/ 5
\n" ); document.write( "m.ananth@hotmail.ca
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