document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785338>Question 785338</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find the value of k so that the line containing the points (6,k) and (&#8722;7,&#8722;4) is parallel to the line containing the points (1,&#8722;9) and (4,&#8722;11). \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477497 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the slope of line joining two points is given by the formula<BR>\n" );
document.write( "(y2-y1)/(x2-x1)=m\r<BR>\n" );
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document.write( "x1		y1	x2	y2				<BR>\n" );
document.write( "1      		-9      	4      	-11    				<BR>\n" );
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document.write( "slope m =		(y2-y1)/(x2-x1)						<BR>\n" );
document.write( "(	-11    	-	-9    	)/(	4    	-	1    	)<BR>\n" );
document.write( "(	-2    	/	3    	)  				<BR>\n" );
document.write( "m=		-  2/ 3						 \r<BR>\n" );
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document.write( "A parallel line will have the same slope\r<BR>\n" );
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document.write( "(6,k) (-7,-4)<BR>\n" );
document.write( "The line joining these points will have slope of -2/3\r<BR>\n" );
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document.write( "(-4-k)/(-7-6)=-2/3\r<BR>\n" );
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document.write( "(-4-k)/-13=-2/3\r<BR>\n" );
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document.write( "-4-k = -13*-2/3\r<BR>\n" );
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document.write( "-4-k = 26/3\r<BR>\n" );
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document.write( "k=-4-26/3\r<BR>\n" );
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document.write( "k=-38/3\r<BR>\n" );
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