document.write( "Question 785372: Wendy took a trip from city A to city B, a distance of 860 mi. She traveled part of the way by bus, which arrived at the train station just in time for Wendy to complete her journey by train. The bus averaged 50 mi/h, and the train averaged 105 mi/h. The entire trip took 9.5 hr. How long did Wendy spend on the train? \n" ); document.write( "
Algebra.Com's Answer #477495 by mananth(16946)\"\" \"About 
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let her travel by bus x miles
\n" ); document.write( "bus rate = 50 mph\r
\n" ); document.write( "\n" ); document.write( "she travels by train 860-x miles
\n" ); document.write( "Train rate = 105 mph\r
\n" ); document.write( "\n" ); document.write( "Time by train + time by bus = 9.5\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "\"%28860-x%29%2F105+%2B%28x%2F50%29+=9.5\"\r
\n" ); document.write( "\n" ); document.write( "lcm of 50 &105 is 5250\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 5250\r
\n" ); document.write( "\n" ); document.write( "50(860-x)+105x=5250 *9.5\r
\n" ); document.write( "\n" ); document.write( "43000-50x+105x=5250*9.5\r
\n" ); document.write( "\n" ); document.write( "55x=(5250*9.5)-43000\r
\n" ); document.write( "\n" ); document.write( "x= 125 miles by bus\r
\n" ); document.write( "\n" ); document.write( "860-125=735 miles by train\r
\n" ); document.write( "\n" ); document.write( "time on train = 735/105 = 7 hours\r
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