document.write( "Question 785327: My thousands digit is 3 times my 100's digit. The sum of my 10's and 1's digit is 1 less than my 1000's digit. My 100's digit is 2 less than my 10's digit. What 4 digit number am I? Please help! Thanks. \n" ); document.write( "
Algebra.Com's Answer #477490 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The four digits: a, b, c, d (a is the thousands)
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\n" ); document.write( "My thousands digit is 3 times my 100's digit.
\n" ); document.write( "a = 3b
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\n" ); document.write( "The sum of my 10's and 1's digit is 1 less than my 1000's digit.
\n" ); document.write( "c + d = a - 1
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\n" ); document.write( "My 100's digit is 2 less than my 10's digit.
\n" ); document.write( "b = c - 2
\n" ); document.write( "or
\n" ); document.write( "c = b + 2
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\n" ); document.write( "Using c + d = a - 1, replace c with (b+2), replace a with 3b
\n" ); document.write( "b + 2 + d = 3b - 1
\n" ); document.write( "d = 3b - b - 1 - 2
\n" ); document.write( "d = 2b - 3
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\n" ); document.write( "Lets assume b = 3, then a = 9,
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\n" ); document.write( "c = 3 + 2
\n" ); document.write( "c = 5
\n" ); document.write( "and
\n" ); document.write( "d = 2(3) - 3
\n" ); document.write( "d = 3
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\n" ); document.write( "9353 is the number
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\n" ); document.write( "or
\n" ); document.write( "Lets assume b = 2, then a = 6,
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\n" ); document.write( "c = 2 + 2
\n" ); document.write( "c = 4
\n" ); document.write( "and
\n" ); document.write( "d = 2(2) - 3
\n" ); document.write( "d = 1
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\n" ); document.write( "6241 is the number
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\n" ); document.write( "I think that is the only two possibilities\r
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