document.write( "Question 785318: Find a linear equation whose graph is the straight line with the given properties.
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Algebra.Com's Answer #477457 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
If the value of \"y\" changes by \"15\" units when the value of \"x\" changes by \"1\",
\n" ); document.write( " then the slope of that line is \"15%2F1=15\"\r
\n" ); document.write( "\n" ); document.write( "and if line goes through (\"23\",\"-5.1\"), then equation will be:\r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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  • it goes through point (23, -5.1)

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  • it has a slope of 15

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\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (23, -5.1) plotted with a little blue dot:
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\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
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\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
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\n" ); document.write( " Given that a=15, and \"system%28+x%5B1%5D+=+23%2C+y%5B1%5D+=+-5.1+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=15%2Ax+%2B+-350.1\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "since you cannot see a line on a graph above, here is another graph: \r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28600%2C+600%2C+-400%2C+400%2C+-400%2C+400%2C+15x-350.1%29+\"
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