document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785255>Question 785255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of raisins worth $1.50 per pound must be mixed with 10 pounds of peanuts worth $1.20 per pound to produce a mixture worth $1.40 per pound?<BR>\n" );
document.write( "Give an numerical answer ONLY. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477420 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is going to require 2 equations\r<BR>\n" );
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document.write( "first one is going to be r + p = 10   (raisins plus peanuts equals 10 pounds)\r<BR>\n" );
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document.write( "our second equation is going to be 1.5r + 1.2p = 1.4 ( $1.50 per pound of raisins added to $1.20 per poind of peanuts will equal our $1.40 mixture)\r<BR>\n" );
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document.write( "we are going to do this using the subtraction method\r<BR>\n" );
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document.write( "r + p = 10<BR>\n" );
document.write( "1.5r + 1.2p = 1.4\r<BR>\n" );
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document.write( "multiply our 1.4 by 10\r<BR>\n" );
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document.write( "r + p = 10<BR>\n" );
document.write( "1.5r + 1.2p = 14\r<BR>\n" );
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document.write( "we want to get rid of the decimal points, so multiply both sides of the bottom equation by 10\r<BR>\n" );
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document.write( "r + p = 10<BR>\n" );
document.write( "15r + 12p = 140\r<BR>\n" );
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document.write( "we want to eliminate one of the variables, so lets multiply the top equation by -12 to get rid of p\r<BR>\n" );
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document.write( "-12r + -12p = -120<BR>\n" );
document.write( "15r + 12p = 140\r<BR>\n" );
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document.write( "add up the two equations\r<BR>\n" );
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document.write( "3r = 20\r<BR>\n" );
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document.write( "divide both sides by 3\r<BR>\n" );
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document.write( "r = 6.66\r<BR>\n" );
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document.write( "now tht we know the value of r, plug it in to find the value of p\r<BR>\n" );
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document.write( "15(6.66) + 12p = 140<BR>\n" );
document.write( "99.9 + 12p = 140\r<BR>\n" );
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document.write( "subtract 99.9 from both sides\r<BR>\n" );
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document.write( "12p = 40.1\r<BR>\n" );
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document.write( "divide both sides by 12\r<BR>\n" );
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document.write( "p = 3.34\r<BR>\n" );
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document.write( "we now have both our values.  you will need 6.66 pounds of raisins and 3.34 pounds of peanuts to have 10 pounds worth $1.40 per pound </SPAN>\n" );
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