document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785259>Question 785259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number is doubled and then decreased by 11. The result is 59. What is the original number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477418 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> our number will be labeled as x\r<BR>\n" );
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document.write( "a number is doubled, so it will start off as 2x\r<BR>\n" );
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document.write( "then decreased by 11, our equation is...\r<BR>\n" );
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document.write( "2x - 11 = 59\r<BR>\n" );
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document.write( "lets solve it\r<BR>\n" );
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document.write( "add 11 to both sides of the equation\r<BR>\n" );
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document.write( "2x = 70\r<BR>\n" );
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document.write( "divide both sides by 2\r<BR>\n" );
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document.write( "x = 35 </SPAN>\n" );
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