document.write( "Question 785218: Can you please help me solve this.
\n" ); document.write( "3/5x + 1/4y = − 11/10
\n" ); document.write( "1/8x =13/24+ 1/3y \n" ); document.write( "

Algebra.Com's Answer #477417 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"3%2F5\"$ x + $\"1%2F4\"$ y = $\"-11%2F10\"$
\n" ); document.write( " $\"1%2F8\"$ x = $\"13%2F24\"$ + $\"1%2F3\"$ y
\n" ); document.write( "First get rid of those annoying fractions,
\n" ); document.write( "multiply the 1st equation by 40, the 2nd equation by 24
\n" ); document.write( "24x + 10y = -44
\n" ); document.write( "3x = 13 + 8y
\n" ); document.write( "Rearrange the 2nd equation
\n" ); document.write( "24x + 10y = -44
\n" ); document.write( "3x - 8y = 13
\n" ); document.write( "multiply the 2nd equation by 8
\n" ); document.write( "24x + 10y = -44
\n" ); document.write( "24x - 64y = 104
\n" ); document.write( "------------------subtraction eliminates x, find y
\n" ); document.write( "74y = -148
\n" ); document.write( "y = -148/84
\n" ); document.write( "y = -2
\n" ); document.write( ":
\n" ); document.write( "Use eq: 3x = 13 + 8y to find x
\n" ); document.write( "3x = 13 + 8(-2)
\n" ); document.write( "3x = 13 - 16
\n" ); document.write( "3x = -3
\n" ); document.write( "x = -1
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "I'll let you get in on the fun, check these solutions in the original equations
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