document.write( "Question 785261: Factor Completely: 64-27u^3
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Algebra.Com's Answer #477415 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"64-27u%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%284%29%5E3-%283u%29%5E3\" Rewrite \"64\" as \"%284%29%5E3\". Rewrite \"27u%5E3\" as \"%283u%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%284-3u%29%28%284%29%5E2%2B%284%29%283u%29%2B%283u%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284-3u%29%2816%2B12u%2B9u%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"64-27u%5E3\" factors to \"%284-3u%29%2816%2B12u%2B9u%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"64-27u%5E3=%284-3u%29%2816%2B12u%2B9u%5E2%29\"
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