document.write( "Question 785147: One jar contains 5/6 alcohol and another 8/9 alcohol. How many liters taken from each jar are required to fill a third jar with a capacity of 24 liters so that the mixture will be 7/8 alcohol? \n" ); document.write( "
Algebra.Com's Answer #477380 by harpazo(655)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is another method:\r \n" ); document.write( "\n" ); document.write( "Let x = litres of alcohol taken from first jar. \n" ); document.write( "Let y = litres of alcohol taken from second jar.\r \n" ); document.write( "\n" ); document.write( "We will need two equations to get value of x and y.\r \n" ); document.write( "\n" ); document.write( "So first equation is our quantity constraint, i.e., we just need total 24 litres.\r \n" ); document.write( "\n" ); document.write( "x + y = 24\r \n" ); document.write( "\n" ); document.write( "Next equation comes from final composition of alcohol.\r \n" ); document.write( "\n" ); document.write( "5x/6 + 8y/9 = 7*24/8\r \n" ); document.write( "\n" ); document.write( "Solving these two, you get \n" ); document.write( "x=6 \n" ); document.write( "y=18\r \n" ); document.write( "\n" ); document.write( "Hope it helps:) \n" ); document.write( " |