document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785149>Question 785149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B working together can finish a piece of work in 20 days. After working together for 4 days, A quits and B finishes the work in 24 days more. Find the number of days it requires each of them to do the work alone. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477377 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Their combined rate of work is 1 job/20 days = 1/20 job/day<BR>\n" );
document.write( "After working together for 4 days, they have completed (1/20)*4 = 1/5 of the job<BR>\n" );
document.write( "B finishes the remaining 4/5 of the job in 24 days, so B's rate of work is 4/5 job/24 days = 1/30 job/day<BR>\n" );
document.write( "Let r = A's rate of work.  Their combined rate = 1/20 = 1/30 + 1/r<BR>\n" );
document.write( "Solve for r:<BR>\n" );
document.write( "1/r = 3/60 - 2/60 = 1/60 job/day<BR>\n" );
document.write( "So B can complete the job in 30 days, A can complete the job in 60 days </SPAN>\n" );
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