document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785081>Question 785081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation of a line perpendicular to the given line but passing through the given point\r<BR>\n" );
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document.write( "y=-x+3; (-2,-2)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477352 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = mx + b is the slope intercept form of a line equation.  m is the slope.  Parallel lines have the same slope.<P><BR>\n" );
document.write( "y=-x+3 the slope is -1.  So the slope of the parallel line is also 1.<P><BR>\n" );
document.write( "y - y(1) = m(x-x(1)) is the point slope form of a line equation where (x(1),y(1)) is a point on the line, and m is the slope.<P><BR>\n" );
document.write( "So the equation of this parallel line is y - (-2) = -1(x-(-2) which is y+2 = -x-2<P><BR>\n" );
document.write( "We can write this in the slope intercept form by subtracting 2 from both sides.<P><BR>\n" );
document.write( "y = -x - 4<P><BR>\n" );
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