document.write( "Question 785009: hello will someone please help me with this question (x-1)/(x+2)=(2x-3)/(x+4) \n" ); document.write( "
Algebra.Com's Answer #477331 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-1%29%2F%28x%2B2%29=%282x-3%29%2F%28x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "cross multiply\r
\n" ); document.write( "\n" ); document.write( "(x-1)(x+4)=(2x-3)(x+2)\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B4%29-1%28x%2B4%29=2x%28x%2B2%29-3%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-x-4=2x%5E2%2B4x-3x-6\"\r
\n" ); document.write( "\n" ); document.write( "re arrange\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-x%5E2%2B4x-3x-4x%2Bx=-4%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-2=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1=+2%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2=3\"\r
\n" ); document.write( "\n" ); document.write( "x+1 = +/- sqrt(3)\r
\n" ); document.write( "\n" ); document.write( "x= 1+sqrt(3) OR 1-sqrt(3)\r
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\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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