document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=784978>Question 784978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this: A rectangle is 4 times as long as it is wide. If the length is increased by 4 inches and the width is decreased by 1 inch,the area will be 60 square inches. What were the dimensions of the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477312 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be w\r<BR>\n" );
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document.write( "length = 4w\r<BR>\n" );
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document.write( "length increased by 4=>4w+4\r<BR>\n" );
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document.write( "width decreased by 1=>w-1\r<BR>\n" );
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document.write( "Area = 60\r<BR>\n" );
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document.write( "Area = l*w\r<BR>\n" );
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document.write( "(w-1)(4w+4)=60\r<BR>\n" );
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document.write( "(w+1)*4(w-1)=60\r<BR>\n" );
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document.write( "(w+1)(w-1)=60/4\r<BR>\n" );
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document.write( "w^2-1=15\r<BR>\n" );
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document.write( "w^2=15+1\r<BR>\n" );
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document.write( "w^2=16<BR>\n" );
document.write( "w=+/-4\r<BR>\n" );
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document.write( "ignore negative length\r<BR>\n" );
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document.write( "w=4 in\r<BR>\n" );
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document.write( "length = 4*4 = 16in\r<BR>\n" );
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document.write( " </SPAN>\n" );
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