document.write( "Question 784795: How much water should be added to 16 mL of 20% alcohol solution to reduce the concentration to 8%?\r
\n" ); document.write( "\n" ); document.write( "The answer is NOT 24 ml like I read on a previous solution on this site!! \n" ); document.write( "
Algebra.Com's Answer #477238 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Yes, it is 24 mL. 0.2 X 16 = 3.2 and 0.08 X 40 = 3.2. 20% of the original 16 mL has the same amount of pure acid as 8% of 40 mL (16 mL of 20% solution plus 24 mL of pure water). If the answer in your book is different, then the answer in your book is either giving you something that you do not recognize as equivalent to 24 mL, or the book is wrong.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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