document.write( "Question 67070This question is from textbook Algebra 1
\n" );
document.write( ": A student walks and jogs to college each day. The student averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and the student makes the trip in 1 hour. How far does the student jog?
\n" );
document.write( "THANK YOU!!! \n" );
document.write( "
Algebra.Com's Answer #47714 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A student walks and jogs to college each day. The student averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and the student makes the trip in 1 hour. How far does the student jog? \n" ); document.write( ": \n" ); document.write( "Let x = the distance jogged \n" ); document.write( "Then (8-x) = distance walked \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Jog time + walk time = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply thru by 45 to get rid of the denominators, resulting in: \n" ); document.write( "5x + 9(8-x) = 45 \n" ); document.write( ": \n" ); document.write( "5x + 72 - 9x = 45 \n" ); document.write( "-4x = 45 - 72 \n" ); document.write( "-4x = -27 \n" ); document.write( "x = -27/-4 \n" ); document.write( "x = + 6.75 km jogged \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: 8 - 6.75 = 1.25 km walked \n" ); document.write( "6.75/9 + 1.25/5 = \n" ); document.write( " .75 + .25 = 1 \n" ); document.write( ": \n" ); document.write( "How about this, did it make sense to you? \n" ); document.write( " \n" ); document.write( " |