document.write( "Question 783973: 2sec^2x=3tanx+1
\n" ); document.write( "solve for interval of 0< x <360 \n" ); document.write( "
Algebra.Com's Answer #477069 by lwsshak3(11628)\"\" \"About 
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2sec^2x=3tanx+1
\n" ); document.write( "solve for interval of 0< x <360
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\n" ); document.write( "2sec^2x=3tanx+1
\n" ); document.write( "2(tan^2x+1)=3tanx+1
\n" ); document.write( "2tan^2x+2=3tanx+1
\n" ); document.write( "2tan^2x-3tanx+1=0
\n" ); document.write( "(2tanx-1)(tanx-1)=0
\n" ); document.write( "2tanx-1=0
\n" ); document.write( "tanx=1/2
\n" ); document.write( "x≈26.57 and 206.57 deg (in quadrant III)
\n" ); document.write( "or
\n" ); document.write( "tanx-1=0
\n" ); document.write( "tanx=1
\n" ); document.write( "x=45 and 225 deg (in quadrant III)\r
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