document.write( "Question 784312: Find the area of a rectangle at 14 feet and 8 inches long/= L and 5 feet and 6 inches wide/= W \n" ); document.write( "
Algebra.Com's Answer #477061 by MathLover1(20849)\"\" \"About 
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the area of a rectangle:\r
\n" ); document.write( "\n" ); document.write( "\"A=LW\" where \"L\" is the length and \"W\" is the width \r
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\n" ); document.write( "\n" ); document.write( " if the length \"L\" is \"14ft\" and \"8in\" and the width \"W\" is \"5ft\" and \"6in\", first convert either inches to feet or feet to inches\r
\n" ); document.write( "\n" ); document.write( "\"1ft=12in\"
\n" ); document.write( "or
\n" ); document.write( "\"1in=%281%2F12%29ft=0.08333ft\"\r
\n" ); document.write( "\n" ); document.write( "so, I would take \"1ft=12in\"\r
\n" ); document.write( "\n" ); document.write( "then \"L=14ft%2B8in=14%2A12in%2B8in=176in\" and \"W=5ft%2B6in=5%2A12in%2B6in=66in\"\r
\n" ); document.write( "\n" ); document.write( "and your area will be:\r
\n" ); document.write( "\n" ); document.write( "\"A=LW\"\r
\n" ); document.write( "\n" ); document.write( "\"A=176in%2A66in\"\r
\n" ); document.write( "\n" ); document.write( "\"A=11616in%5E2\"\r
\n" ); document.write( "\n" ); document.write( "or in square feet\r
\n" ); document.write( "\n" ); document.write( "\"1in%5E2=0.006944ft%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"A=11616%2A0.006944ft%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"A=80.67ft%5E2\"\r
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