document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=784100>Question 784100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/(x-3)+3 = 15/(x-3)? Im confused on how to go about solving it... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477001 by </B><A HREF=/tutors/aboutme.mpl?userid=wilft1><B>wilft1(217)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wilft1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=wilft1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/(x-3) + 3 = 15/(x-3)\r<BR>\n" );
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document.write( "trying to get x on one side of the equation...\r<BR>\n" );
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document.write( "divide both sides by the reciprocal of 3/x-3  which is x-3/3\r<BR>\n" );
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document.write( "x-3/3 / 3/(x-3) + 3 = 15/(x-3)times x-3/3\r<BR>\n" );
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document.write( "3 = x15-45/x3-9\r<BR>\n" );
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document.write( "3= x5-5\r<BR>\n" );
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document.write( "add 5 to both sides\r<BR>\n" );
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document.write( "8 = x5\r<BR>\n" );
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document.write( "divide both sides by 5\r<BR>\n" );
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document.write( "x = 8/5 </SPAN>\n" );
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