document.write( "Question 67078: how do you factor this\r
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document.write( "2x^2-x-10 \n" );
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Algebra.Com's Answer #47695 by Zoop(21)![]() ![]() ![]() You can put this solution on YOUR website! When factoring a trinomial, simply find two factors of the third term that add to get the second term's coefficient.\r \n" ); document.write( "\n" ); document.write( "For \n" ); document.write( "\n" ); document.write( "-5 * 2 \n" ); document.write( "-2 * 5\r \n" ); document.write( "\n" ); document.write( "Obviously, nothing is working, which is an unfortunate side effect of this technique. \r \n" ); document.write( "\n" ); document.write( "So we'll use the British method. The British method requires you to multiply the third time by the coefficient of the first term, which in this case is -10 * 2, -20.\r \n" ); document.write( "\n" ); document.write( "Then, do the same thing you did with the first technique (finding to factors to add to the second term) with this new number, -20. \r \n" ); document.write( "\n" ); document.write( "-5 * 4 \n" ); document.write( "-4 * 5\r \n" ); document.write( "\n" ); document.write( "Wouldya look at that! -5 and 4 add to get -1, which is the coefficient of -x. \r \n" ); document.write( "\n" ); document.write( "So now we take -5 and 4 and put both of them over the first term, this time, just without the power.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, just use these and factor.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Final? \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And you're done.\r \n" ); document.write( "\n" ); document.write( "See if that works out for you. =) \n" ); document.write( "-Zoop \n" ); document.write( " |