document.write( "Question 783558: A product is formed by arranging 5 different letters from the collection (B, H, Q, T, W, Z) one after another.
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document.write( "a) How many different such product codes are there? My answer- 720\r
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document.write( "b) How many of them contain the letter W?\r
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document.write( "If you could please just help me get started with solving part B I would really appreciate it!! Thanks! \n" );
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Algebra.Com's Answer #476836 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You did part A correctly: the permutations of 6 things taken 5 at a time. For part B, consider the number of codes that DO NOT contain the letter W. Hint: Permutations of 5 things taken 5 at a time. All of these are counted in the 720 you got for part A, so if you eliminate the ones that DON'T have a W, you are left with the number that do.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |