document.write( "Question 783533: Find the specified domain\r
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document.write( "For g(x)=√x+2 and h(x)= 1/x-3, what is the domain of h o g?\r
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document.write( "This is what I worked out but I am certain it is incorrect.\r
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document.write( "h(g(x))= 1/(√x+2)-3\r
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document.write( "x+2=0
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document.write( "x=-2\r
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document.write( "Domain: (-∞, -2)∪(-2, ∞) \n" );
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Algebra.Com's Answer #476822 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the specified domain \n" ); document.write( "For g(x)=√(x+2) and h(x)= 1/(x-3, what is the domain of h o g? \n" ); document.write( "This is what I worked out but I am certain it is incorrect. \n" ); document.write( "------------------------ \n" ); document.write( "h(g(x))= h[g(x)] = h[sqrt(x+2) = 1/[sqrt(x+2)-3] \n" ); document.write( "------ \n" ); document.write( "x+2 must be >= 0 \n" ); document.write( "x must be >= -2 \n" ); document.write( "---- \n" ); document.write( "But: sqrt(x+2)-3 cannot be zero. \n" ); document.write( "sqrt(x+2) # 3 \n" ); document.write( "x+2 # 9 \n" ); document.write( "x # 7 \n" ); document.write( "--------- \n" ); document.write( "Domain of hog is [-2,7)U(7,+oo) \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===============\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |