document.write( "Question 783533: Find the specified domain\r
\n" ); document.write( "\n" ); document.write( "For g(x)=√x+2 and h(x)= 1/x-3, what is the domain of h o g?\r
\n" ); document.write( "\n" ); document.write( "This is what I worked out but I am certain it is incorrect.\r
\n" ); document.write( "\n" ); document.write( "h(g(x))= 1/(√x+2)-3\r
\n" ); document.write( "\n" ); document.write( "x+2=0
\n" ); document.write( "x=-2\r
\n" ); document.write( "\n" ); document.write( "Domain: (-∞, -2)∪(-2, ∞)
\n" ); document.write( "

Algebra.Com's Answer #476822 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find the specified domain
\n" ); document.write( "For g(x)=√(x+2) and h(x)= 1/(x-3, what is the domain of h o g?
\n" ); document.write( "This is what I worked out but I am certain it is incorrect.
\n" ); document.write( "------------------------
\n" ); document.write( "h(g(x))= h[g(x)] = h[sqrt(x+2) = 1/[sqrt(x+2)-3]
\n" ); document.write( "------
\n" ); document.write( "x+2 must be >= 0
\n" ); document.write( "x must be >= -2
\n" ); document.write( "----
\n" ); document.write( "But: sqrt(x+2)-3 cannot be zero.
\n" ); document.write( "sqrt(x+2) # 3
\n" ); document.write( "x+2 # 9
\n" ); document.write( "x # 7
\n" ); document.write( "---------
\n" ); document.write( "Domain of hog is [-2,7)U(7,+oo)
\n" ); document.write( "===================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );