document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=783449>Question 783449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cant get the  solution correct: 3/5 (x-2)-1/4 (2x-7) &#8804; 3\r<BR>\n" );
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document.write( "I tried mulitplying by the LCM 20 to get rid of the fractions and then this is how it goes from here:\r<BR>\n" );
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document.write( "12(x-2)-5(2x-7)&#8804; 60<BR>\n" );
document.write( "12x-24-10x+35 &#8804; 60<BR>\n" );
document.write( "2x-11 &#8804; 60<BR>\n" );
document.write( "  +11  +11\r<BR>\n" );
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document.write( "2x &#8804; 71<BR>\n" );
document.write( "2x/2 &#8804; 71/2\r<BR>\n" );
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document.write( "x &#8804; 71/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476781 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12x-24-10x+35 &#8804; 60<P><BR>\n" );
document.write( "2x-11 &#8804; 60...That's the mistake...35 is positive, 24 is negative, the result is + 11.<P><BR>\n" );
document.write( "2x+11 <= 60<P><BR>\n" );
document.write( "2x <= 49<P><BR>\n" );
document.write( "x <= 49/2 </SPAN>\n" );
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