document.write( "Question 783235: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 87. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #476773 by Cromlix(4381)\"\" \"About 
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Jack is 4 times as old as Lacy
\n" ); document.write( "J = 4L
\n" ); document.write( "6 years from now the sum of their ages will be 87.
\n" ); document.write( "J + 6 + L + 6 = 87
\n" ); document.write( "Replace J with 4L from 1st equation
\n" ); document.write( "4L + 6 + L + 6 = 87
\n" ); document.write( "Collect like terms.
\n" ); document.write( "4L + L = 87 - 12
\n" ); document.write( "5L = 75
\n" ); document.write( "L = 15
\n" ); document.write( "Current ages:
\n" ); document.write( "Lacy = 15 years old
\n" ); document.write( "Jack = 60 years old.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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