document.write( "Question 783235: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 87. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #476773 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Jack is 4 times as old as Lacy \n" ); document.write( "J = 4L \n" ); document.write( "6 years from now the sum of their ages will be 87. \n" ); document.write( "J + 6 + L + 6 = 87 \n" ); document.write( "Replace J with 4L from 1st equation \n" ); document.write( "4L + 6 + L + 6 = 87 \n" ); document.write( "Collect like terms. \n" ); document.write( "4L + L = 87 - 12 \n" ); document.write( "5L = 75 \n" ); document.write( "L = 15 \n" ); document.write( "Current ages: \n" ); document.write( "Lacy = 15 years old \n" ); document.write( "Jack = 60 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |