document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=783437>Question 783437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the equation is: 2x^2+2y^2+4y=0 and I am supposed to find the center and the radius of the circle as well as the x and y intercepts but I am not sure how to find the center and radius. If you could help me find those I can find the x and y intercepts. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476762 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2+2y^2+4y=0 and I am supposed to find the center and the radius of the circle <BR>\n" );
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document.write( "Complete the square on the x-terms and on the y-terms:::<BR>\n" );
document.write( "2(x^2) + 2(y^2+2y) = 0<BR>\n" );
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document.write( "2(x-0)^2 + 2(y^2+2y+1) = 2<BR>\n" );
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document.write( "2(x-0)^2 + 2(y+1)^2 = 2<BR>\n" );
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document.write( "(x-0)^2 + (y+1)^2 = 1<BR>\n" );
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document.write( "Center: (0,-1)<BR>\n" );
document.write( "Radus : sqrt(2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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