document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=783421>Question 783421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of 2 (angle 2) is 7° larger than the measure of 1. The measure of 3 is 7° larger than the measure of 2. Find each angle measure\r<BR>\n" );
document.write( "\n" );
document.write( "I know a triangle must add up to 180 degrees. These are interior angles. I also know that I need to set up a formula and I dont know how. So far I tried x+x+7+x+7=180 but its not working. Any help would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476751 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the measure of 1<BR>\n" );
document.write( "then x+7 is the measure of angle 2<BR>\n" );
document.write( "and x+7+7 is the measure of angle 3<BR>\n" );
document.write( "so we have x +x+7 +x+14 =180<BR>\n" );
document.write( "3x +21 = 180<BR>\n" );
document.write( "3x = 159<BR>\n" );
document.write( "x = 53<BR>\n" );
document.write( "angle 1 = 53<BR>\n" );
document.write( "angle 2 = 60<BR>\n" );
document.write( "angle 3 = 67<BR>\n" );
document.write( "and 53 +60 +67 = 180<BR>\n" );
document.write( "180 = 180<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );