document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=783425>Question 783425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 1,872 ft2. The ratio of the length to the width is 9:13. Find the perimeter of the rectangle. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476746 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width and y = length\r<BR>\n" );
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document.write( "x/y = 9/13\r<BR>\n" );
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document.write( "xy = 1872\r<BR>\n" );
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document.write( "x = 9y/13\r<BR>\n" );
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document.write( "9y^2/13 = 1872\r<BR>\n" );
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document.write( "y^2 = 2704\r<BR>\n" );
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document.write( "y = 52\r<BR>\n" );
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document.write( "x = 36\r<BR>\n" );
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document.write( "Perimeter = 2(36+52) = 176\r<BR>\n" );
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document.write( "If you need more help with similar questions you can contact me now at:\r<BR>\n" );
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document.write( "mthman@gmail.com\r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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