document.write( "Question 783407: I'm not sure how to solve this or where to even begin. \r
\n" ); document.write( "\n" ); document.write( "A chemist wants to dilute her 5L stock of 30% solution of acid to 15%. How much 10% solution does she have to add to the 30% solution in order to obtain a mixture that is 15% acid?
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Algebra.Com's Answer #476742 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = liters of 10% solution to be added
\n" ); document.write( "\"+.1x+\" = liters of acid in 10% solution
\n" ); document.write( "\"+.3%2A5+=+1.5+\" liters of acid already in 30% solution
\n" ); document.write( "------------------
\n" ); document.write( "\"+%28+.1x+%2B+1.5+%29+%2F+%28+x+%2B+5+%29+=+.15++\"
\n" ); document.write( "\"+.1x+%2B+1.5+=+.15%2A%28+x+%2B+5+%29+\"
\n" ); document.write( "\"+.1x+%2B+1.5+=+.15x+%2B+.75+\"
\n" ); document.write( "\"+.05x+=+.75+\"
\n" ); document.write( "\"+x+=+15+\"
\n" ); document.write( "15 liters of 10% solution need to be added
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+.1x+%2B+1.5+%29+%2F+%28+x+%2B+5+%29+=+.15++\"
\n" ); document.write( "\"+%28+.1%2A15+%2B+1.5+%29+%2F+%28+15+%2B+5+%29+=+.15++\"
\n" ); document.write( "\"+%28+1.5+%2B+1.5+%29+%2F+20+=+.15+\"
\n" ); document.write( "\"+3+=+.15%2A20+\"
\n" ); document.write( "\"+3+=+3+\"
\n" ); document.write( "OK
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