document.write( "Question 783408: Hi I would like some help in solving to find the x and y intercepts of the equation: y=x^2-6x+8
\n" ); document.write( "For the Y-intercept I was able to get that y=8 but I am not sure if that is right and I cant solve for x. If you could help me that would be greatly appreciated. \n" ); document.write( "

Algebra.Com's Answer #476729 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "No. Your

-intercept is not right. An intercept is a point. A point in

is designated by an ordered pair. The number 8 is not an ordered pair. The

-coordinate of the

-intercept is, indeed, 8. The

-coordinate of any

-intercept is zero. Hence your

-intercept is the point

.\r
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\n" ); document.write( "\n" ); document.write( "To find the

-intercepts, first find the zeros of the quadratic function. In other words, set the function equal to zero and solve by any convenient means. Hint: this one factors over the integers. Note that -2 times -4 = 8 and -2 plus -4 = -6. Once you have the two zeros of the function,

and

, you can form the ordered pairs that represent the two

-intercepts thus:\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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