document.write( "Question 783376: How many liters of a 1% solution must be added to 12 liters of a 4%solution to obtain a 2% solution? \n" ); document.write( "

Algebra.Com's Answer #476725 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = liters of 1% solution needed
\n" ); document.write( " $\"+.01x+\"$ = liters of chemical in 1% solution
\n" ); document.write( " $\"+.04%2A12+=+.48+\"$ liter of chemical in 4% solution
\n" ); document.write( "------------------
\n" ); document.write( " $\"+%28+.01x+%2B+.48+%29+%2F+%28+x+%2B+12+%29+=+.02+\"$
\n" ); document.write( " $\"+.01x+%2B+.48+=+.02%2A%28+x+%2B+12+%29+\"$
\n" ); document.write( " $\"+.01x+%2B+.48+=+.02x+%2B+.24+\"$
\n" ); document.write( " $\"+.01x+=+.24+\"$
\n" ); document.write( " $\"+x+=+24+\"$
\n" ); document.write( "24 liters of 1% solution are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.01x+%2B+.48+%29+%2F+%28+x+%2B+12+%29+=+.02+\"$
\n" ); document.write( " $\"+%28+.01%2A24+%2B+.48+%29+%2F+%28+24+%2B+12+%29+=+.02+\"$
\n" ); document.write( " $\"+%28+.24+%2B+.48+%29+%2F+36+=+.02+\"$
\n" ); document.write( " $\"+.72+=+.02%2A36+\"$
\n" ); document.write( " $\"+.72+=+.72+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

\n" );