document.write( "Question 783314: Two cyclists race one against the other on a 500 m circular track, leaving together from the starting line and each one doing 10 laps. Knowing that the first cyclist travels at a speed of 55km/h and the second one travels at a speed of 20km/h, when will the first cyclist overtake the second by four laps? \n" ); document.write( "
Algebra.Com's Answer #476706 by ankor@dixie-net.com(22740)\"\" \"About 
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wo cyclists race one against the other on a 500 m circular track, leaving together from the starting line and each one doing 10 laps.
\n" ); document.write( " Knowing that the first cyclist travels at a speed of 55km/h and the second one travels at a speed of 20km/h, when will the first cyclist overtake the second by four laps?
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\n" ); document.write( "These are some fast runners||
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\n" ); document.write( "4 laps is a total of 4(500) = 2000 m; change this to 2 km (speed in km/hr)
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\n" ); document.write( "When will the two runners be 2 km apart?
\n" ); document.write( "Let t = elapsed time for this to be true.
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\n" ); document.write( "Write a dist equation; dist = speed * time
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\n" ); document.write( "Fast runner d - slow runner d = 2
\n" ); document.write( "55t - 20t = 2
\n" ); document.write( "35t = 2
\n" ); document.write( "t = 2/35
\n" ); document.write( "t = .057 hrs, .057(60) = 3.43 minutes
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\n" ); document.write( "Response
\n" ); document.write( "I assumed when they used the word \"when\" it meant how long it took the faster
\n" ); document.write( "runner to be 4 laps ahead of slow runner, 4 laps being 2 km \n" ); document.write( "
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