document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=783343>Question 783343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man mixes candy worth 70 centavos per pound with a candy worth 40 centavos per pound to make 42 pounds of assortment worth 50 centavos per pouns. how much  of each kind should be used ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476683 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  a man mixes candy worth 70 centavos per pound with a candy worth 40 centavos per pound to make 42 pounds of assortment worth 50 centavos per pouns. how much of each kind should be used ?<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "40x + 70(42-x) = 50*42<BR>\n" );
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document.write( "40x + 70*42 - 70x = 50*42<BR>\n" );
document.write( "-30x = -20*42<BR>\n" );
document.write( "x = (2/3)42<BR>\n" );
document.write( "x = 28 lbs (amt of 40 cent candy needed)<BR>\n" );
document.write( "42-x = 14 lbs (amt of 70 cent candy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );