document.write( "Question 783310: Write in slope-intercept form (if possible) and standard form an equation of the line described\r
\n" ); document.write( "\n" ); document.write( "perpendicular to 4x – 3y = 2 and contains (1, 2)
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Algebra.Com's Answer #476659 by mananth(16946)\"\" \"About 
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4 x + -3 y = 2
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-3 y = -4 x + 2
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 1 1/ 3 x + - 2/3
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1 1/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal - 3/4
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be - 3/4
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\n" ); document.write( "m= - 3/4 ,point ( 1 , 2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "2 = - 3/ 4 + b
\n" ); document.write( "b= 11/4
\n" ); document.write( "m= - 3/4
\n" ); document.write( "The required equation is y = - 3/ 4 x + 11/ 4 \r
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\n" ); document.write( "multiply by 4\r
\n" ); document.write( "\n" ); document.write( "4y=-3x+11\r
\n" ); document.write( "\n" ); document.write( "3x+4y=11
\n" ); document.write( "m.ananth@hotmail.ca
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