document.write( "Question 783242: if a container currently has 30% solutions and you want it to be 50% solution. how much should you replace with 100% soulution? \n" ); document.write( "
Algebra.Com's Answer #476647 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The capacity of the full container is not given. Call it C. The volume, v units of solution would be removed and replaced with v units of the 100% pure material to increase the percentage concentration. The volume of mixture before and after the change is the same.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%28C%2A30-v%2A30%2Bv%2A100%29%2FC=50%29\"
\n" ); document.write( "You can solve for v in terms of C. \r
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\n" ); document.write( "\n" ); document.write( "\"C%2A30%2B%28100-30%29v=50C\"
\n" ); document.write( "\"70v=50C-30C\"
\n" ); document.write( "\"70v=20C\"
\n" ); document.write( "\"7v=2C\"
\n" ); document.write( "\"highlight%28v=%282%2F7%29C%29\"
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