document.write( "Question 783242: if a container currently has 30% solutions and you want it to be 50% solution. how much should you replace with 100% soulution? \n" ); document.write( "
Algebra.Com's Answer #476647 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! The capacity of the full container is not given. Call it C. The volume, v units of solution would be removed and replaced with v units of the 100% pure material to increase the percentage concentration. The volume of mixture before and after the change is the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "You can solve for v in terms of C. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |