document.write( "Question 783102: Last year, Carlos had 20000 to invest. He invested some of it in an account that paid 9% simple interest per year, and he invested the rest in an account that paid 5% simple interest per year. After one year, he received a total of 1160 in interest. How much did he invest in each account? \n" ); document.write( "
Algebra.Com's Answer #476622 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 9.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 5.00% per annum ------------ Amount invested = y \n" ); document.write( " 20000 \n" ); document.write( "Interest----- 1160.00 \n" ); document.write( " \n" ); document.write( "Part I 9.00% per annum ---x \n" ); document.write( "Part II 5.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 20000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "9.00% x + 5.00% y= 1160 \n" ); document.write( "Multiply by 100 \n" ); document.write( "9 x + 5 y= 116000.00 --------2 \n" ); document.write( "Multiply (1) by -9 \n" ); document.write( "we get \n" ); document.write( "-9 x -9 y= -180000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -4 y= -64000 \n" ); document.write( "divide by -4 \n" ); document.write( " y = 16000 - x) \n" ); document.write( "Part I 9.00% $ 4000 \n" ); document.write( "Part II 5.00% $ 16000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "4000 --------- 9.00% ------- 360.00 \n" ); document.write( "16000 ------------- 5.00% ------- 800.00 \n" ); document.write( "Total -------------------- 1160.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |