document.write( "Question 783105: how many liters of a 10% alcohol solution must be mixed with how many liters of a 50% solution to get 20 liters of a 40% solution? \n" ); document.write( "

Algebra.Com's Answer #476621 by mananth(16946) $\"\"$ $\"About$

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percent ---------------- quantity
\n" ); document.write( "Alcohol type I 10.00% ---------------- x liters
\n" ); document.write( "Alcohol type II 50.00% ------ 20 - x liters
\n" ); document.write( "Mixture 40.00% ---------------- 20
\n" ); document.write( "Total 20 liters
\n" ); document.write( "10.00% x + 50.00% ( 20 - x ) = 40.00% * 20
\n" ); document.write( "10 x + 50 ( 20 - x ) = 800
\n" ); document.write( "10 x + 1000 - 50 x = 800
\n" ); document.write( "10 x - 50 x = 800 - -1000
\n" ); document.write( "-40 x = -200
\n" ); document.write( "/ -40
\n" ); document.write( " x = 5 liters 10.00% Alcohol type I
\n" ); document.write( " 15 liters 50.00% Alcohol type II
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\n" ); document.write( "m.ananth@hotmail.ca
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