document.write( "Question 782884: A woman is 61(1/12) inches tall and her son is 59(1/9) inches tall. How much taller is the woman? \n" ); document.write( "
Algebra.Com's Answer #476599 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The difference in their heights is
\n" ); document.write( "\"61%261%2F12-59%261%2F9\"
\n" ); document.write( "The result is \"1%2635%2F36\" inches of difference in their heights (almost 2 inches).
\n" ); document.write( "The mother is \"1%2635%2F36\" inches taller (almost 2 inches taller).
\n" ); document.write( "That makes sense because the approximation, calculated dropping the timy \"1%2F12\" and \"1%2F9\" fractions is
\n" ); document.write( "61 inches - 59 inches = 2 inches.
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\n" ); document.write( "When we have to add or subtract fractions, we need a common denominator.
\n" ); document.write( "In this case, I would choose, \"36\", because it the smallest common multiple of \"12\" and \"9\":
\n" ); document.write( "\"12%2A3=36\"} and \"9%2A4=36\"
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\n" ); document.write( "THE HARD WAY:
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\n" ); document.write( "That result can be simplified;
\n" ); document.write( "\"71%2F36=%2836%2B35%29%2F36=36%2F36%2B35%2F36=1%2B35%2F36=1%2635%2F36\"
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\n" ); document.write( "MY WAY:
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\n" ); document.write( "Sadly, teachers will probably favor the \"HARD WAY\".
\n" ); document.write( "It requires more complicated calculations, and mistakes are more likely, but students can memorize and (at least temporarily) remember a recipe to calculate the result. Understanding why such calculation are done that way; how and why calculations could be done differently, and/or how to estimate the result could be valuable bonuses.
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