document.write( "Question 782912: I want to find out how much water needs to be added to one gallon of a 75% phosphoric acid solution to create a 6% acid solution. \n" ); document.write( "
Algebra.Com's Answer #476597 by josgarithmetic(39617)\"\" \"About 
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75% phosphoric acid is about 11.67 pounds per gallon. The percentage is expected weight per weight.
\n" ); document.write( "Water is 8.345 pounds per gallon.\r
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\n" ); document.write( "\n" ); document.write( "Let w = how many pounds of water to add.\r
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\n" ); document.write( "\n" ); document.write( "\"11.67%2A0.75%2F%28w%2B11.67%29=0.06\", as decimal fractions instead of as percents.
\n" ); document.write( "\"6%28w%2B11.67%29=11.67%2875%29\"
\n" ); document.write( "\"6w=%2811.67%29%2875%29-6%2811.67%29\"
\n" ); document.write( "\"6w=11.67%2875-6%29\"
\n" ); document.write( "\"6w=11.67%2869%29\"
\n" ); document.write( "\"w=%2811.67%29%2869%29%2F6\"
\n" ); document.write( "\"highlight%28w=134%29\" pounds of water.\r
\n" ); document.write( "\n" ); document.write( "As volume, \"134%2F8.345=highlight%2816.1%29\" gallons of water.
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