document.write( "Question 67022: how to do these equations\r
\n" ); document.write( "\n" ); document.write( "(-4+3i)+(6-10i)\r
\n" ); document.write( "\n" ); document.write( "(1-4i)-(-3+5i)\r
\n" ); document.write( "\n" ); document.write( "(-2+3i)*(4-8i)\r
\n" ); document.write( "\n" ); document.write( "(-1+2i)/(-3+4i)
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Algebra.Com's Answer #47659 by venugopalramana(3286)\"\" \"About 
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how to do these equations
\n" ); document.write( "(-4+3i)+(6-10i)
\n" ); document.write( "ADD/SUBTRACT IMAGINARY NUMBERS WITH 'I'S AND REAL NUMBERS WITHOUT 'I'S SEPARATELY
\n" ); document.write( "=(-4+6)+I(3-10)=2-7I\r
\n" ); document.write( "\n" ); document.write( "(1-4i)-(-3+5i)
\n" ); document.write( "=(1+3)+I(-4-5)=4-9I\r
\n" ); document.write( "\n" ); document.write( "(-2+3i)*(4-8i)
\n" ); document.write( "[-2*4]+[-2*(-8)+(3)(4)]I+(3)(-8)I^2..............I^2=-1...HENCE
\n" ); document.write( "[-8+24]+I[16+12]=16+28I\r
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\n" ); document.write( "\n" ); document.write( "(-1+2i)/(-3+4i).........MULTIPLY AND DIVIDE WITH -3-4I
\n" ); document.write( "[(-1+2I)(-3-4I)]/[(-3+4I)(-3-4I)]
\n" ); document.write( "=(3-2I-8I^2)/(9-16I^2)
\n" ); document.write( "=(11-2I)/(25)
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