document.write( "Question 782858: solve
\n" ); document.write( "2x=sqrt20+2x
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Algebra.Com's Answer #476571 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
2x= sqrt(20+2x)\r
\n" ); document.write( "\n" ); document.write( "(2x)^2 = 20+2x\r
\n" ); document.write( "\n" ); document.write( "4x^2 = 2x+20\r
\n" ); document.write( "\n" ); document.write( "4x^2-2x-20=0\r
\n" ); document.write( "\n" ); document.write( "2x^2-x-10 = 0\r
\n" ); document.write( "\n" ); document.write( "x = 5/2 or x = -2\r
\n" ); document.write( "\n" ); document.write( "Answer: x = 5/2\r
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\n" ); document.write( "\n" ); document.write( "If you need more help with similar questions you can contact me now at:\r
\n" ); document.write( "\n" ); document.write( "mthman@gmail.com\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
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