document.write( "Question 782788: If an equilateral triangle is circumscribed about a circle of radius 10 cm, determine the side of the triangle. \n" ); document.write( "
Algebra.Com's Answer #476570 by KMST(5328)\"\" \"About 
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Side AC is tangent to the circle, perpendicular to radius OD at the point of tangency (point D).
\n" ); document.write( "We can draw \"6\" angles congruent with AOD connecting the center with points of tangency and vertices, and their measures add to \"360%5Eo\",
\n" ); document.write( "so AOD measures \"360%5Eo%2F6=60%5Eo\"
\n" ); document.write( "Using trigonometry, we know that
\n" ); document.write( "\"DA%2FOD=tan%2860%5Eo%29\" --> \"DA%2F10cm=sqrt%283%29\" --> \"DA=%2810cm%29%2Asqrt%283%29\"
\n" ); document.write( "and since \"CD+=+DA\",
\n" ); document.write( "\"CA+=+CD%2BDA=+2DA+=2%2A%2810cm%29%2Asqrt%283%29=20%2Asqrt%283%29\"\"cm\"
\n" ); document.write( "Rounding, we get an approximmate value of \"highlight%2834.64cm%29\".
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